New way of class creation using "type"

[Humble]

We were following below syntax to create a class :

>>>> class sports():
...     def __init__(self):
...             print "I am constructor"
... 
>>> type(sports)
<type 'classobj'>


How-ever its also possible to create a class using "type" as shown below.

type requires 3 arguments..



First arg: This should be the name of the class

Second arg: This should be the tuple from where the new class is inheriting.. This can be a just a placeholder though with ().

Third arg : This is the dictionary of variables and functions which this class holds..

For ex:

>>>> def footm(self):
...     print "I am football"
... 
>>> football = type("football", (sports,object),{"foot":footm, "x":5})
>>> sports
<class __main__.sports at 0x7f7ad30c7bb0>



Obviously method of resolution will be in this order:

>(<class '__main__.football'>, 
<class __main__.sports at 0x7f7ad30c7bb0>,
 <type 'object'>)


Now, we can get methods and variables ..

>>>> f=football()
I am constructor

>>> f.foot()
I am football
>>><


hope it helps!

[Humble]

Please understand , this is really useful for dynamic class creation, how-ever may not be suitable for longer class declarations..

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