Do I need "-Wstrict-prototypes " when compiling C programs..?

[Humble]

Yes, I would say: What that option mean to you/compiler ?

       -Wstrict-prototypes (C and Objective-C only)
           Warn if a function is declared or defined without specifying the argument types.  (An old-style function definition is permitted
           without a warning if preceded by a declaration that specifies the argument types.)




hmmm.. lets try to compile the same program which used in earlier topics.

[hchiramm@humbles-lap C-Pgm]$ gcc -Wall -Wstrict-prototypes -ansi -pedantic -c compile.c 
compile.c:3:5: warning: function declaration isn’t a prototype [-Wstrict-prototypes]
 int main ()
     ^
[hchiramm@humbles-lap C-Pgm]$ 



now change the program a bit by respecting the warning.. 

# include <stdio.h>

int main (int argc, char *argv[])
{

	printf ("\n I was told to compile ");
	return 0;
}
[hchiramm@humbles-lap C-Pgm]$ 



Recompile,

[hchiramm@humbles-lap C-Pgm]$ gcc -Wall -Wstrict-prototypes -ansi -pedantic -c compile.c 
[hchiramm@humbles-lap C-Pgm]$ 



No Errors!! cool, but Is this option really required ? 

depends.. find the answer .. but always good to have it in your compiler string..

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