try, except, else , finally in python

[Humble]

try:
  will try to execute
except exception1:
  have to act on exception1, if occurred
except exception2:
  have to act on exception2, if occurred 
else:
  I will execute if there was NO EXCEPTION 
finally:
  You can not skip me, I will always execute regardless there was exception  or not...


Isnt it clear from above? if not please let me know..

>>> try:
...     fd = open("/root/ad.txt","r")
... except e:
...     print e
... 
Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
IOError: [Errno 13] Permission denied: '/root/ad.txt'
>>> 

>>> e
IOError(13, 'Permission denied')
>>> e.args
(13, 'Permission denied')
>>> try:
...     fd = open("/root/ad.txt","r")
... except IOError,e:
...     print e
... finally:
...     print "I am done"
... 
[Errno 13] Permission denied: '/root/ad.txt'
I am done
>>> type(e)
<type 'exceptions.IOError'>
>>> e
IOError(13, 'Permission denied')

>>> e.args
(13, 'Permission denied')
>>> 


Also you can use only except: which will capture any exceptions from try block. Also its possible to give a list of exceptions using a tuple.

except (exception1, exception2):

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